Algebraic Fractions - Questions

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Question 1
17617

Simplify: \(\dfrac{{{m^2} + 4m}}{{{m^2} + m - 12}}\)

\(\dfrac{m}{{m - 3}}\)

\[\frac{m^{2}+4m}{m^{2}+m-12}=\frac{m\cancel{(m+4)}}{\cancel{(m+4)}(m-3)}=\frac{m}{m-3}\]

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