Binomial Expansion - Questions

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Question 1
17538

\({(2x - 1)^3} = ?\)

\(8{x^3} - 12{x^2} + 6x - 1\)

\begin{aligned}
(2x-1)^{3} &=(2 x)^{3}+3(2x)^{2} \times(-1)+3(2 x) \times(-1)^{2}+(-1)^{3} \\
&=8x^{3}-12x^{2}+6 x-1
\end{aligned}

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