🔒 Unlock Full Access

You're currently viewing a preview. Sign up or log in to access all 5 questions and complete solutions.

Question 1
28627

The height \(h\) metres of a stone, \(t\) seconds after being thrown vertically upwards is given by \(h = 40t - 5{t^2}\). At what time is it first at 60 m?

\(t = 2\) seconds

\begin{align}
&\begin{aligned}
h&=40 t-5 t^{2} \\
60&=40 t-5 t^{2}
\end{aligned}\\
&\begin{aligned}
5 t^{2}-40 t+60&=0 \\
5\left(t^{2}-8 t+12\right)&=0 \\
5(t-2)(t-6)&=0 \\
\end{aligned}\\
&\therefore t=2 \text { or } t=6\\
&\therefore t=2 \text { seconds } \\
\end{align}

📚 Want More Questions?

There are 4 more questions available. Create your free account to access the complete question set with detailed solutions.