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Solving Cubic Inequalities - Questions

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Question 1
28673

Solve \(\left( {x - 2} \right)\left( {x + 2} \right)\left( {x + 3} \right) \le 0\)

\(\left( { - \infty , - 3} \right] \cup \left[ { - 2,2} \right]\)

From the graph of 
\(\left( {x - 2} \right)\left( {x + 2} \right)\left( {x + 3} \right)\)
the solution is \((-\infty,-3]\cup [-2,2]\)

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