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Question 1
19206

Solve \(\sin x = \dfrac{1}{2}\) for \(x \in [0,2\pi ]\)

\(x = \dfrac{\pi }{6},x = \dfrac{{5\pi }}{6}\)

\[
\sin x=\frac{1}{2} \rightarrow x=\frac{\pi}{6} \text { or } x=\pi-\frac{\pi}{6}=\frac{5 \pi}{6}
\]

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