Graphs of y = asinn(t+-c) +-b and y=acosn(t+-c)+-b - Questions

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Question 1

19221

The correct equation for the adjacent function is?

\(y = 2\sin (x + \dfrac{\pi }{2})+1\)

\(y = 2\cos (x + \dfrac{\pi }{2})+1\)

\(y = 2\sin (x + \dfrac{\pi }{2})-1\)

\(y = 2\cos (x + \dfrac{\pi }{2})-1\)

Answer

\(y = 2\sin (x + \dfrac{\pi }{2})+1\)

Worked Solution

\begin{align}
&\text{Consider } y=2 \sin \left(x+\frac{\pi}{2}\right)+1\\
&\text {when } x=0 \quad y=2 \sin \frac{\pi}{2}+1=3 \quad \therefore A
\end{align}

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