The formula \(R = \dfrac{1}{x} - \dfrac{1}{y}\) is rearranged to make \(y\) the subject. What is this new formula?
Answer
\(y = {\rm{ }}\dfrac{x}{{1 - Rx}}\)
Worked Solution
Question 2
10855
Using the formula \(a = \dfrac{{2Rn}}{{n + 1}}\),what is the value of \(n\) when \(a = 36\) and \(R = 12\)?
Answer
-3
Worked Solution
Question 3
10856
Using the formula \(S = \dfrac{n}{2}\left( {a + l} \right)\),what is the value of \(a\) when \(S = 284,n = 16\) and \(l = 8\)?
Answer
27.5
Worked Solution
Question 4
13187
Given that \({v^2}\) = \({u^2} + 2as\) and \(u = 5 , v = 8\) and \(a = 2\) the value of \(s\) is?
Answer
\(s = 9.75\)
Worked Solution
Question 5
29331
Make \(x\) the subject of \(\dfrac{{ax - by}}{c} = b - x\)
Answer
\(x = \dfrac{{b(c + y)}}{{a + c}}\)
Worked Solution
$$ \begin{aligned} \frac{a x-b y}{c} &=b-x \\ a x-b y &=c(b-x) \\ a x-b y &=c b-c x \\ a x+c x &=b c+b y \\ x(a+c) &=b c+b y\\ x&=\frac{b(c+y)}{a+c} \end{aligned} $$
