The Inclusion–Exclusion Principle - Questions - Class Mathematics School Portal

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Question 1

56553

Answer

$8$

Worked Solution

$$
\begin{aligned}
|A \cup B|&=|A|+|B|-|A \cap B| \\
\{A \cap B\}&=\{5,6\} \\
\therefore|A \cup B|&=5+5-2 \\
&=8
\end{aligned}
$$

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