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Question 1
21016

Solve \(\tan x = - 1,x \in \left( { - \pi ,\pi } \right)\)

\(x = \frac{{3\pi }}{4}, - \frac{\pi }{4}\)

$$
\tan \left(\pi-\frac{\pi}{4}\right)=-1 \rightarrow x=\frac{3 \pi}{4} \text {or}\ \tan \left(-\frac{\pi}{4}\right)=-1 \rightarrow x=\frac{-\pi}{4}
$$

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