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Question 1
61455

Find the inverse matrix of \(\left[ {\begin{array}{*{20}{c}}2&3\\3&4\end{array}} \right]\)

\(\left[ {\begin{array}{*{20}{c}}{ - 4}&3\\3&{ - 2}\end{array}} \right]\)

$$
\begin{aligned}
\left[\begin{array}{ll}
a & b \\
c & \alpha
\end{array}\right]^{-1} &=\frac{1}{a d-b c}\left[\begin{array}{cc}
\alpha-b \\
-c a
\end{array}\right] \\
\left[\begin{array}{ll}
2 & 3 \\
3 & 4
\end{array}\right] &=\frac{1}{8-9}\left[\begin{array}{cc}
4-3 \\
-3 & 2
\end{array}\right] \\
&=\left[\begin{array}{cc}
-4 & 3 \\
3 & -2
\end{array}\right]
\end{aligned}
$$

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