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Question 1
61412

A particle of mass 4kg is suspended by two strings attached to two points in the same horizontal plane. If the two strings make angles with the horizontal, find the tension in each string. 

\(T_1=T_2=2 \sqrt2 \,kg\,wt\)

$$\begin{aligned}
&\triangle ABC\ \text{is the triangle}\\
&\text{of the resolved forces.}\\
&\begin{aligned}A B&=T_{1}, \quad B C=T_{2}\ \text{and}\\ A C&=4 \text{kgwt.}\\
\angle A B C&=90^{\circ}\\
T_{1}&=T_{2} ( \text{isosceles}\ \Delta)\\
\frac{T_{2}}{4}&=\cos 45^{\circ}\\
T_{2}&=4 \times \frac{\sqrt{2}}{2}\\
\therefore\ T_{1}&=T_{2}=2 \sqrt{2} \mathrm{~kgwt} .\end{aligned}
\end{aligned}
$$

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