\(x=0.7 \text{ or } x=4.3\)

\begin{align}
&x^{2}-5 x+3=0\\
&\text{Comparing with the standard equation,} \\&a=1, b=-5, c=3\\
&\begin{aligned}
x&=\frac{-(-5) \pm \sqrt{(-5)^{2}-4 \times 1 \times 3}}{2 \times 1}\\
x&=\frac{5 \pm \sqrt{13}}{2}\\
\end{aligned}\\
&\begin{array}{lrl}
x=\dfrac{5-3.60555 \ldots}{2} &\text{ or }& \dfrac{5+3.60555 \ldots}{2}\\
x=0.69722 \ldots & \text{ or } & 4.30277 \ldots\\ x \approx 0.7&\text{ or } &4.3
\end{array}
\end{align}