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Question 1
42993

Solve \(4x^2=25\)

\(x=\pm \dfrac{5}{2}\)

$$
\begin{aligned}
4x^2&=25\\
x^2&=\frac{25}{4}\\
x&=\pm\sqrt{\frac{25}{4}}\\
\therefore x&=\pm \frac{5}{2}
\end{aligned}
$$

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