Question 1
34979

Solve \(  3x^2+5x=9 \) by completing the square. 

\(x=-\dfrac{5\pm\sqrt{133}}{6}\)

Question 2
34980

Solve \(  3x^2+2x-2=0 \) by completing the square. 

\(x=-\dfrac{1\pm\sqrt7}{3}\)

Question 3
34981

Solve \(  2x^2+x-4=0 \) by completing the square. 

\(x=-\dfrac{1\pm\sqrt{33}}{4}\)

Question 4
34982

Solve \(  4x^2+4x-5=0 \) by completing the square. 

\(x=\dfrac{-1\pm\sqrt6}{2}\)

Question 5
34973

Solve \(x^2-4x=21\) by completing the square. 

\(x=7 \text{ or } x=-3\)

Question 6
34974

Solve \( x^2-8x=18  \) by completing the square. 

\(x=4 \pm \sqrt {34}\)

Question 7
34975

Solve \(  x^2+6x-11=0 \) by completing the square. 

\(x= -3 \pm 2\sqrt5\)

Question 8
34976

Solve \( 2x^2-8x=18  \) by completing the square. 

\(x=2\pm\sqrt{13}\)

Question 9
34977

Solve \(  2x^2+6x-11=0 \) by completing the square. 

\(x=-\dfrac{3 \pm \sqrt{31}}{2}\)

Question 10
34978

Solve \( x^2-5x=4  \) by completing the square. 

\(x=\dfrac{5\pm\sqrt{41}}{2}\)

Question 11
18916

Factorise by completing the square: \(y={x^2}+6x+13\)

\(y\; = \;{\left( {x + 3} \right)^2} + 4\)

Question 12
18917

Factorise by completing the square: \(y\; = \;{x^2}-8x+21\)

\(y\; = \;{\left( {x - 4} \right)^2} + 5\)

Question 13
18918

Factorise by completing the square: \(y=3{x^2}-6x-9\)

\(y=3{\left( {x - 1} \right)^2} - 12\)

Question 14
18919

Factorise by completing the square: \(y\; = \; -{x^2}+4x+7\)

\(y\; = \; - {\left( {x - 2} \right)^2} + 11\)

Question 15
13201

By completing the square the solutions to \(x^2 - 10x - 11=0\) are?

\(x = 11,\,x = - 1\)

Question 16
13202

By completing the square the solutions to \(x^2 - 5x + 3=0\) are?

\(x = \dfrac{{5 \pm \sqrt {13} }}{2}\)

Question 17
13203

By completing the square the solutions to \(2x^2 + 13x - 7=0\) are? 

\(x = - 7,\,x = \dfrac{1}{2}\)

Question 18
13204

By completing the square the solutions to \(2{x^2} + 6x - 5=0\) are?

\(x = \dfrac{{ - 3 \pm \sqrt {19} }}{2}\)

Question 19
13205

By completing the square the solutions to \(2{x^2} + 3x - 1 = 0\) are?

\(x = \dfrac{{ - 3 \pm \sqrt {17} }}{4}\)

Question 20
15731

By completing the square, the solutions to \({x^2} - 6x + 3 = 0\) are?

\(x = 3 \pm \sqrt 6 \)