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Question 1
62554

For the parabola \(f(x)=x(x-2)\), find

i) the \(x\) intercepts

ii) the equation of the axis of symmetry

iii) the vertex

i)  \(x = 0\) and \(x = 2\)

ii)  \(x = 1\)

iii)  Vertex is \((1, - 1)\)

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