Question 1
19201

Use the graph of \(f(x) = 1 - {x^2}\) to sketch the graph of \(y = \dfrac{1}{{f(x)}}\).

Refer to the worked solutions for sketch of graph

Question 2
19344

Use the graph of \(f(x) = 1 - x\) to sketch the graph of \(y = \dfrac{1}{{f(x)}}\)

Refer to the worked solutions for sketch of graph

Question 3
19345

Use the graph of \(f(x) = 2x\left( {x - 1} \right)\) to sketch the graph of \(y = \dfrac{1}{{f(x)}}\).

Refer to the worked solutions for sketch of graph

Question 4
19346

Use the graph of \(f(x) = 3{x^2} - {x^3}\) to sketch the graph of \(y = \dfrac{1}{{f(x)}}\).

Refer to the worked solutions for sketch of graph

Question 5
14015

Given that \(f(x) = {x^2}\) then \(g(x) = \dfrac{1}{{f(x)}}\) is? 

A.
B.
C.
D.

\(C\)

Question 6
14016

Given that \(f(x) = x - 1\) then \(g(x) = \dfrac{1}{{f(x)}}\) is?

A.
B.
C.
D.

\(A\)

Question 7
14017

Given that \(f(x) = {x^2} - 1\) then \(g(x) = \dfrac{1}{{f(x)}}\) is? 

A.
B.
C.
D.

\(D\)

Question 8
14018

Given that \(f(x) = {(x + 1)^2}\) then \(g(x) = \dfrac{1}{{f(x)}}\) is? 

A.
B.
C.
D.

\(C\)

Question 9
14019

Given that \(f(x) = {(x - 1)^2} + 1\,\) then \(g(x) = \dfrac{1}{{f(x)}}\) is? 

A.
B.
C.
D.

Graph A