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Year 11 Maths - General Linear Relations and Equations

Substitution of Values Into a Formula

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Questions
Question 1
19662

The time, \(T\) seconds, it takes to swing back and forth once is \(T = 2\pi \sqrt {\dfrac{l}{g}} \), where \(l\,\text{m}\) is the length of the swing and \(g\) is the gravitational acceleration. Find \(T\), if \(l=2.45~\text{m}\) and \(g = 10~\text{ms}^{- 2}\)

\(3.1~\text {seconds}\)

\begin{align}
T&=2 \pi \sqrt{\frac{2.45}{10}}\\
&=2 \pi \sqrt{0.245}\\
&=3.1 \text { seconds }
\end{align}

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