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Year 11 Maths - Methods Circular functions

Defining Trigonometric Functions: Sine And Cosine

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Questions
Question 1
19030

Find the value of \(\sin \dfrac{{3\pi }}{2}\)

\(-1\)

\begin{align}
\sin \frac{3 \pi}{2} &=\sin \left(\pi+\frac{\pi}{2}\right) \\
&=-\sin \frac{\pi}{2} \\
&=-1
\end{align}

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