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Year 11 Maths - Methods Counting methods

Pascal’s triangle and the binomial theorem

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Questions
Question 1
84345

Expand \((x+3)^3\) using Pascals triangle

\(x^3+9x^2+27x+27\)

\begin{align}
(x+3)^3&=1 \times x^3+3 \times x^2 \times 3+ 3 \times x \times 3^2+1 \times 3^3\\
&=x^3+9x^2+27x+27
\end{align}

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