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Year 11 Maths - Methods Polynomials

Families Of Cubic Polynomial Functions

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Questions
Question 1
28679

The point \((1, - 1)\) lies on \(y = a{\left( {x - 2} \right)^3} + 1\). Find the value of \(a\).

\(a =  2\)

\begin{aligned}
y&=a(x-2)^{3}+1 \\
-1&=a(1-2)^{3}+1 \\
-1&=-a+1 \\
-a&=-2 \\
\therefore a&=2
\end{aligned}

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