Year 11 Maths - Methods Quadratics

Graphing Quadratics In Polynomial Form

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Questions

Question 1

61797

A parabola has \(x\)-axis intercepts \(6\) and \(10\). State the \(x\)-coordinate of the vertex.

Answer

\(x=8\)

Worked Solution

\begin{align}
&\text{The vertex lies on the axis of symmetry}\\
&\text{of the parabola.}\\
&\text{The equation of the axis of symmetry}\\
&\text{is the midpoint of the x-intercepts}\\
&\begin{aligned}
\therefore \quad x&=\frac{6+10}{2} \\
x&=8
\end{aligned}
\end{align}

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