Year 11 Maths - Specialist Circular functions

The tangent function

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Questions

Question 1

21016

Solve $\tan x = - 1,x \in \left( { - \pi ,\pi } \right)$

Answer

$x = \frac{{3\pi }}{4}, - \frac{\pi }{4}$

Worked Solution

$$
\tan \left(\pi-\frac{\pi}{4}\right)=-1 \rightarrow x=\frac{3 \pi}{4} \text {or}\ \tan \left(-\frac{\pi}{4}\right)=-1 \rightarrow x=\frac{-\pi}{4}
$$

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