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Year 9 Maths Indices and Surds

Index Law 3 and Zero Power

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Question 1
42739

Simplify \(-5{{\left({p}^{3}{q}^{2} \right)}^{0}} \)

\(-5\)

$$
\begin{aligned}
-5(p^3q^2)^0&=-5p^{3\times 0}q^{2\times 0}\\
&=-5p^{0}q^{0}\\
&=-5\times 1\times 1\\
&=-5
\end{aligned}
$$ As any number raised to the power of zero is equal to 1.

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